Answer to Question #224687 in General Chemistry for xax

Question

An aqueous solution is made from 0.798 g of potassium permanganate, KMnO4. If the volume of solution is 50.0 mL, what is the molarity of KMnO4 in the solution?

(1 moL = 158.03 g KMnO4)

Answer 1

Moles of $KMnO4 = \frac{0.798}{158.03}=0.05$ moles

$Morality=\frac{0.05}{0.05}=1 .0M$