Answer to Question #224395 in General Chemistry for Queen

Question

How much heat is needed to raise the temperature of a pot containing 1800 grams of water on the stove from 45 degrees Celsius to 100 degrees Celsius? The specific heat capacity of water is 4.18 J/g degrees Celsius.

Answer 1

Parameters;

$m = 1800g\\ T_1= 45°C\\ T_2 = 100°C\\ ∆T = 100°C- 45°C = 55°C\\ c = 4.18\ J/g°C$

Using,

$Q = mc∆\theta\\ Q = 1800× 4.18 × 55\\ Q = 413820J\\ \therefore Q= 413.82\ kJ$

This means that 413.82kJ of heat is needed to raise the temperature of a pot containing 1800 grams of water on the stove from 45 degrees Celsius to 100 degrees Celsius.