Question #223697

A student buys a rope at the store the label on the packaging says that the rope is 2.1 5M in length the student measures the rope is 1.8 5M what is the students percent error

Expert's answer

To calculate the percentage error, we use the equation**:**

We are given**:**

Length of rope measured by student = 1.85 m

Actual length of the rope = 2.15 m

2.15 - 1.85/1.85 × 100

Hence, the percentage error of the student is 13.95 %.

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