Answer to Question #222781 in General Chemistry for Shari

Question

In order to verify the heat of reaction a chemist mixes 1 L of 1MNAOH and 1 L of 1MHCL the initial temperature of the two solutions is 25°C the specific heat of water is 4.184 J program for Celsius the enthalpy of reaction of the following is -58 kJ per mole considering only the specific heat of the 2 L of water and no heat transfer to or from the surroundings what is the final temperature of the solution?

Answer 1

q=mcsΔT=mcs(Tfinal−Tinitial)=(4.184J/g°C)×(800g)×(X−25)°C=(4.184J/g°C)×(800g)×(64)°C=210,000J(=210kJ)

= 79°C