Answer to Question #222723 in General Chemistry for Hamo

Question #222723
Calculate the amount of CaCo3 that would remain if 17g of CaCo3 are reacted with 0.25moles of dilute HCL
1
Expert's answer
2021-08-03T05:14:50-0400

CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)

Molar Mass of CaCO3 =100.0869 g/mol

Mole ratio = 2:1

= 0.125 × 100.0896

= 12.5112

= 17-12.5112

= 4.49g


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