Question

50 centimeters cubed of 1.0M suphuric acid was reacted with 3.2 g of metal carbonate m₂(co₃) culculate the random atomic mass of the fomula m₂ c o₃

Answer 1

$Molarity = \frac{moles}{volume}$

$Moles= molarity ×volume$

$Moles = 1.0× 0.050=0.05moles$

Random atomic mass = $=\frac{3.2}{0.05}=64g/mol$