Answer to Question #220632 in General Chemistry for Nooner

Question #220632

What is the pH of a titration of 0.077 L of 0.5M HCl when 0.019 L of 0.25M NaOH have been added?


1
Expert's answer
2021-07-26T06:33:56-0400

0.5 - 0.25 = 0.25

0.25/0.096

2.604

PH + POH = 14

pOH=−log([OH-])

= -0.416

pH = 14+0.416

= 14.42


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