Answer to Question #219915 in General Chemistry for Tally

Question #219915
A gas occupied a volume of 5dm^3 at 2atm and 273
1
Expert's answer
2021-07-26T01:26:05-0400

p x V = n x R x T

5 dm3 = 5 L

10 °C = 10 + 273 = 283 K

2 atm x 5 L = n x 0.082 atm•L/(mol•K) x 283 K

n = 2 atm x 5 L / (0.082 atm•L/(mol•K) x 283 K) = 0.43 mol


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