Question #218760

Calculate the mass of iodine that must be

reacted with excess phosphorus to produce

5.00 g of phosphorus(III) iodide according to

the equation below.

2P+3I2 → 2PI3

Expert's answer

**Solution.**

"xg" "500g"

"2P+3I_2 \u2192 2PI_3"

"3 Mr(I_2)" "2Mr(PI_3)"

"\\dfrac{x}{3Mr(I_2)}=\\dfrac{500}{2Mr(PI_3)};"

"x=\\dfrac{500\\sdot3Mr(I_2)}{2Mr(PI_3)};"

"x=\\dfrac{500\\sdot3\\sdot126.9\\sdot2}{2\\sdot(31+126.9\\sdot3)}=462g;"

**Answer: **"462g."

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