CH3NH2 + H2O <-> CH3NH3+ + OH-
Ka = 2.33x10^-11
Given the CH3NH2 concentration is 1.5M, what is the equilibrium concentration of Ch3NH2, CH3NH3+, OH-?
2.33× 10-11 = 1.5 × x
= 2.33/1.5
× = 1.533M
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