Answer to Question #218515 in General Chemistry for Aliah

Question

What will be the value of the universal gas constant if pressure in kPa and volume is in liters?

Answer 1

R=8.314∙m³∙Pa∙K^-1

M∙mol^-1

R=8.314•m3•Pa•K−1•mol−1

But 1∙m³≡1000∙L

1•m3≡1000•L

… and so R=8.314∙1000∙L∙Pa∙K^-1∙mol^-1

R=8.314•1000•L•Pa•K^-1•mol^-1

…and we could take the 1000

1000 multiplier and attach it to the pressure…

R=8.314∙L∙1000×Pa∙K^-1∙mol^-1

R=8.314•L•1000×Pa•K−1•mol−1

…but of course 1000×Pa≡kPa

1000×Pa≡kPa

R=8.314∙L∙kPa∙K^-1∙mol^-1