Question #218515

What will be the value of the universal gas constant if pressure in kPa and volume is in liters?

Expert's answer

R=8.314∙m^{3}∙Pa∙K^{-1}

M∙mol^{-1}

R=8.314•m3•Pa•K−1•mol−1

But 1∙m^{3}≡1000∙L

1•m3≡1000•L

… and so R=8.314∙1000∙L∙Pa∙K^{-1}∙mol^{-1}

R=8.314•1000•L•Pa•K^{-1}•mol^{-1}

…and we could take the 1000

1000 multiplier and attach it to the pressure…

R=8.314∙L∙1000×Pa∙K^{-1}∙mol^{-1}

R=8.314•L•1000×Pa•K−1•mol−1

…but of course 1000×Pa≡kPa

1000×Pa≡kPa

R=8.314∙L∙kPa∙K^{-1}∙mol^{-1}

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