Answer to Question #214054 in General Chemistry for Nnumu

Question #214054

calculate the emf of cell at 298 k sn/sn2+ (.1m)/ag+(.1m)/ag


1
Expert's answer
2021-07-15T02:40:19-0400

E Cell = E° - 0.0592/n log( sn2+)

sn/sn2+

E Cell = 0.89 - 0.0592/2 log(0.1×1)/0.1

= 0.89 -0

= 0.89V


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