Answer to Question #212301 in General Chemistry for ganza

Question

With strong heating, calcium carbonate undergoes

thermal decomposition:

CaCO3 (s) CaO (s) 1 CO2 ( g)

a Write a word equation for the change.

b How many moles of CaCO3 are in 50 g of calcium

carbonate? (Ar : Ca 5 40, C 5 12, O 5 16.)

c i What mass of calcium oxide is obtained from

the thermal decomposition of 50 g of calcium

carbonate, assuming a 40% yield ?

ii What mass of carbon dioxide will be given

off at the same time?

iii What volume will this gas occupy at rtp?

Answer 1

a)$CaCO 3 ​ →CaO+CO 2 ​$

b) Moles of CaCO3=4.37moles

c) I) Mass of calcium oxide =28g

ii)Mass of carbon dioxide=16.7g

iii)Volume=203cm3