Answer to Question #210439 in General Chemistry for Zeff Zeffir

Question #210439

πΎπ‘Ž (𝑁𝐻4 +) = 10βˆ’9 = 𝑁𝐻3 [𝐻3𝑂 +] [𝑁𝐻4 +] = π‘₯ βˆ— π‘₯ 0.1 βˆ’ π‘₯ β‰ˆ π‘₯ 2 0.1 β‡’ π‘₯ =


1
Expert's answer
2021-06-25T05:43:46-0400

Ans:-

"\\to \ud835\udc3e\ud835\udc4e (\ud835\udc41\ud835\udc3b4 ^+)={NH_3}{[H_3O^+][NH_4^+]}" for weak electrolyte


"10^{-9}=x^2\\times{(0.1-x)}"


We know that "\\ \\ \\ \\ 0.1 \u2212 \ud835\udc65 \u2248 0.1"

"10^{-9}=x^2\\times{0.1}\\Rightarrow x=10^{-4}"


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