Answer to Question #210148 in General Chemistry for melo

Question

A gaseous mixture contains 414.0 Torr H

2

(g),

414.0 Torr H2⁡(g), 331.3 Torr N

2

(g),

331.3 Torr N2⁡(g), and 75.7 Torr Ar(g).

75.7 Torr Ar(g). Calculate the mole fraction, 𝜒,

χ, of each of these gases.

Answer 1

We can express the mole fraction χ

i

 of an individual gas i

 in a mixture in terms of the component's partial pressure P

i

:

χi=PiPtotal

Then

Pi=χiPtotalPH₂=414.0 Torr

PN₂=331.3 Torr

PAr=75.7Torr

Ptotal=(414.0 + 331.3 + 75.7) Torr

= 821Torr

χH₂=414Torr/821Torr

=0.5043

χN₂=331.3Torr/821Torr

=0.404

Par = 75.7/821

= 0.0922