Answer to Question #207987 in General Chemistry for kunal gounder

Question

A sample of a gas expands from 2.00 L to 3.50 L against a constant pressure of 1.0 atm. Calculate the work done in joules. (1 L.atm = 101.3 J)

 

A.  1.50 J

B.  +152 J

C.  -152 J

D.   481 J

Answer 1

$A=p∆V;$

$∆V=3.50-2.00=1.50 L;$

$A=1.0×1.50=1.50 L×101.3J$

$A=151.95J$