Answer to Question #207901 in General Chemistry for rache

Question

hand sanitizer recipe has an H2O2 concentration of 0.88molL-1. What volume of 9.8molL-1 H2O2 would be required to make up 500mL of the hand sanitizer.

Answer 1

molarity in sanitiser = 0.88 mol/l

molarity needed = 9.8 mol/l

volume of sanitiser = 500 ml

Moles of sanitiser needed in 1 ltr of sanitiser = 0.88

So, volume of H₂O₂ needed to make 1 ltr of solution = 0.88 * 22.4 ltr

Now we know that

M₁V₁ = M₂V₂

0.88 * 0.88 * 22.4 = 9.8 * V₂

V₂ = 1.77 ltr