Write the electrochemical shorthand notation for a voltaic cell with the following reactions: (3 marks)
Pb2+(aq) + 2e- ⇌ Pb(s) E = -0.13V
Co2+(aq) + 2e- ⇌ Co(s) E = -0.28V
b) Write down the reaction that occurs at the anode. Is this oxidation or reduction?
c) Which substance would form the negative electrode?
d) What would be the potential difference measured by a voltmeter for this cell?
a) Electrochemical notation
Pb | Pb2+ (1M) || CO2+ (1M)| CO
b) Reaction that occurs at the anode
Co2+(aq) + 2e- ⇌ Co(s)
It is Oxidation
c) reaction that occurs at the negative electrode
Pb2+(aq) + 2e- ⇌ Pb(s)
d) potential differences is the sum of the volts within a reaction
= -0.13 + - 0.28