# Answer to Question #205330 in General Chemistry for lea

Question #205330

Zinc metal reacts with hydrochloric acid according to the following balanced equation: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) When 0.119 g of Zn(s) is combined with enough HCl to make 51.3 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 22.5 ∘C to 24.1 ∘C. Part A Find ΔHrxn for this reaction as written. (Use 1.00 g/mL for the density of the solution and 4.18 J/(g⋅∘C) as the specific heat capacity.) Express your answer in kilojoules per mole to two significant figures.

1
Expert's answer
2021-06-10T03:35:21-0400

Mass of solution = volume x density

= 54.5 x 1.0 = 54.5 g

Heat released by reaction = heat absorbed by solution

= mass x specific heat x temperature change of solution

= 54.5 x 4.18 x (24.7 - 22.4)

= 523.963 J

Moles of Zn = mass/molar mass of Zn

= 0.104/65.41 = 0.001590 mol

ΔH = -heat released by reaction/moles of Zn

= -523.963/0.001590

= -3.30 x 105 J/mol = -330 kJ/mol

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

#### Comments

No comments. Be the first!

### Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS