Question #204199

Calculate the final temperature that results from mixing 245 grams of cobalt, specific heat 0.446 J/g0C, at 1420C with 106 grams of water at 24.80C.

Expert's answer

Heat needed to raise water to 100"^0" C:

"0.106\\times4.18\\times(100-24.8)=.331Kj"

heat needed to change water to steam"= 2264.76kJ\/kg\\times0.106= 240kj"

Heat needed to raise steam from 100 to Tf.

"0.106\\times2kj\/kg\\times(Tf-100)=???"

Now, heat given off by cooling Cobalt:

"0.245\\times0.446\\times(tf-1460)"

sums of heats = 0

"0.245\\times0.446\\times(tf-1460)-240-0.106\\times2kj\/kg\\times(Tf-100)-0.331=0"

Now solve for "T_f" and easily get your answer.

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