Answer to Question #203757 in General Chemistry for demy

Question

2N_{2 (g)} +5O_{2 (g)} +2H₂ O_(l)  4HNO_{3 (aq)}, ΔH₁ = -255 kJ

Η_{2 (g)} + 1/2O_{2 (g)} H₂O_{( l)}, ΔH₂ = - 256 kJ

S_(s) + H_{2 (g)} +2O_{2 (g)}  H₂SO_{4 (aq)}, ΔH₃ = - 814 kJ

N_{2 (g)} + 2O_{2 (g)}  2NO_{2 (g)}, ΔH₄ = +66 kJ

Να υπολογίσετε την πρότυπη ενθαλπία της αντίδρασης:

6HNO _(aq) + S_(s)  H₂ SO_{4 (aq)} 6NO _(g) 2H₂ O _{(l )}

Answer 1

$Ht= H1+H2 +H3$ + H4

Ht= -255+ -256+-814+66

Ht=1259kJ