Determine the concentration (in mol / L) of a solution formed from 6.34 g of iron (III) borate and 150 ml of water.
C(in moles)=V(substance)/V(solution)
n(FeBO3)=m(FeBO3)/M(FeBO3)=6.34g/115g/mol=0.06mol
V(FeBO3)=1.23l
V(solution)=1.23l+0.15l=1.38l
C=1.23l/1.38l=0.9mol
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