A 0.100 M solution of a weak acid, HX, has a pH of 2.610. What is the value of Ka for HX?
1)6.03 x 10 -6
2)6.03 x 10 -4
3)2.45 x 10 -2
4)2.45 x 10 -1
5)6.03 x 10 -5
6)2.45 x 10 -3
The K
a
expression is:
Ka=[A-M-][H3O)O+][HA]
=x×x0.100−x
∴ Ka=x2
0.100−x
=0.100^2
= 2.45 × 102
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