Answer to Question #202827 in General Chemistry for Jagjit Singh

Question #202827

When sodium chloride reacts with a silver nitrate silver chloride precipitates what mass of a AgCl it’s produce from 75.0 g of AgNO3

1
Expert's answer
2021-06-04T11:34:02-0400

NaCl+AgNO3→AgCl+NaNO3

Mole ratio = 1:1

Molar Mass of AgNO3 = 169.87

= 75/169.87

= 0.442 mol

Molar Mass of AgCl = 143.32

= 143.32 × 0.442

= 63.278g



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