A 250.0-mg sample of an organic weak acid is dissolved in an appropriate solvent and titrated with 0.0556 M NaOH, requiring 32.58 mL to reach the end point. Determine the compound’s equivalent weight.
Moles of titrant
The moles of NaOH needed to reach the end point are:
moles of NaOH
Wt. of analyte=250 X10-3 g
This gives an equivalent weight of analyte:
E .W. = (g analyte/mole titrant)