Answer to Question #202759 in General Chemistry for Sally

General Chemistry

Question #202759

how to prepare a 5moldm^-3 HCl solution from 12moldm^-3and 2moldm^-3HCl solution

Expert's answer

v=m/M

v(HCl)=5mol

5mol=m/36.6g/mol

m=183g

v(HCl)2=12+2=14mol

m(HCl)=14mol*36.6g/mol=512.4g

w=183g/512.4g*100%=35.71%

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