Question #202525

What molal solution is made when adding 90 grams of K2SO4 to 0.55 kg of water?

Expert's answer

Morality is defined as number of moles of solute dissolved in per kg of solvent.

It is denoted by m.

m = "\\frac{number of moles of solute}{weight of solvent in kg}"

Moles of solute = weight of K_{2}SO_{4}"\\div" molar mass of K_{2}SO_{4}

Molar mass of K_{2}SO_{4}= 2×39 + 1×32 +4×16 =174g/mol

Moles of K_{2}SO_{4}= "\\frac{ 90}{174}= 0.52 mole"

Now

Molality = "\\frac{0.52 mole}{0.55kg }= 0.96 molar"

**The solution is 0.96 molar. **

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