Question #202239

A neon gas at 1 atm has a volume of 12.0 L and a temperature of 44°C. Find the new volume of the gas after the temperature has been increased to 85°C.

Expert's answer

"\\frac {V_1} {T_1}=\\frac{V_2}{T_2}"

"V_2=\\frac {12.0L\u00d7358K}{317K}"

V2=13.55L

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