Nitric acid is formed by the reaction of nitrogen dioxide with water: 3NO₂(𝑔) + H₂O(ℓ) → NO(𝑔) + 2HNO₃(𝑎𝑞) How many grams of nitrogen monoxide, NO, are produced when 180.2 g of H₂O react with nitrogen dioxide?
First we must calculate the amount (in moles) of water:
Now, the amount (in moles) of nitrogen monoxide would be the same as that of water reacted:
Finally, we can calculate the mass of the nitrogen monoxide formed:
"m(NO) = n(NO)\\cdot M(NO)=10.00mol\\cdot 30.01g\/mol=300.1g."