Answer to Question #201202 in General Chemistry for Trail Blazer

Question

The decomposition of N2O5 from the equation below

2N2O5 ----> 4NO2 + O2 has a rate of law of 1×10–³s-¹.

What is the rate of reaction when the concentration of

N2O5 is 0.0001mol/L.

Answer 1

rate of reaction = k [N₂O₅]

rate of reaction = 1×10^-3 × [0.0001]

rate of reaction = 1× 10^-3 × [ 1× 10^-3 ]

rate of reaction = 1 × 10^-6 $molL^{-1}s^{-1}$