Answer to Question #201015 in General Chemistry for Coen Leonard

Question #201015

How many grams of PbCl2 can be produced from the addition of 42 mL of a 0.86 M Pb(NO3)2 solution to 142 mL of 0.65 M NaCl?

1
Expert's answer
2021-05-31T05:57:54-0400

At first, we have to balance the equation between NaCl and Pb(NO3)2 to find the stoichiometry and which compound is the one that limits the reaction:



Then, we calculate how much volume of NaCl solution has to react with the Pb(NO3)2:




This means that Pb(NO3)2 is the limiting reagent (because we have more than the 111.14 mL of NaCl solution at the start), thus we use that reagent volume to calculate the amount of PbCl2 produced:




In conclusion, 10.045 g of PbCl2 were produced on this reaction where Pb(NO3)2 was the limiting reagent.


Reference:

  • Chang, R. (2010). Chemistry. McGraw-Hill, New York.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS