Question #200461

A 2-meter copper conductor which has a cross-sectional area of 8 x 10 – 7 m2 has a potential energy difference of 6 volts between its ends. The resistivity of copper is 1.7 x 10 – 8 Ω-m. Find:

a. The resistance of the conductor, and

b. The current passing through it

Expert's answer

"R = \\rho\\frac{L}{A}"

Where

R = is the resistance

"\\rho" = is the resistivity

L= is the length

A = is the cross sectional area

"R= 1.7\u00d710^{-8}\\Omega m[\\frac{2m}{8\u00d710^{-7}m^2}]"

"R=\\frac{3.4\u00d710^{-8}\\Omega m^2}{8\u00d710^{-7}m^2}"

"R= 0.0425\\Omega"

Current passing

"V= IR"

Where

V = is the potential

I = is the current

R = is the resistance

"I = \\frac{V}{R}"

"I =\\frac {6V}{0.0425\\Omega}= 14.11" amp

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