Question #200350

Butane, C4H10, is an easily liquefied gaseous fuel. Calculate the density of butane gas at 0.897 atm and 24°C. Give the answer in grams per liter

Expert's answer

"T = 273+24=297 K."

"R= 0.082"

"P=0.897" atm

PV = RT

"V=\\frac{RT}{P}"

"V=\\frac{0.082\u00d7297}{0.897}= 26.97= 26970cm^3\/mole" =

Molar mass of "C_4H_{10}= 56g\/mole"

Density "= \\frac{56}{26970}= 0.002 g\/cm^3"

Learn more about our help with Assignments: Chemistry

## Comments

Khuziwe Sithole02.06.21, 20:16You're helping me so much!❤

## Leave a comment