Answer to Question #198753 in General Chemistry for Sebastian

Question

how many mL of H2SO4 are neutralized if it takes 28.03 mL of 3.55 M NaOH to neutralize a 0.25 sample of H2SO4

Answer 1

H₂SO₄(aq)+2NaOH(aq)$\to$ Na₂SO₄(aq)+2H₂O(l)

Moles of NaOH=(28.03*3.55)/1000=0.0995065moles

If 2=0.0995065moles

$\therefore$ 1=(1/2)*0.0995065

=0.0497533moles

Volume of H₂SO₄=(0.0497533moles*1000)/0.25

=199.013mL