Answer to Question #198727 in General Chemistry for Hager Albaher

Question #198727

How many grams of anhydrous remains when 40.0g of KAl(SO4)2 . 12H2O is heated until all water has been liberated?


1
Expert's answer
2021-05-26T07:07:29-0400

Upon heating, the water liberates according to the equation:

KAl(SO4)2*12H2O --> KAl(SO4)2 + 12H2O


The molar mass of KAl(SO4)2*12H2O is 474.39 g/mol

The molar mass of anhydrous KAl(SO4)2 is 258.21 g/mol


Therefore,


Answer: 21.8 g


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