Answer to Question #198690 in General Chemistry for Tayla

Question

the temperature of a gas started at 312 with a yolume of 4.5 L increased to 372 with a new volume of 1.2 what would the new pressure be if the initial pressure was 1.1 atm

Answer 1

$\frac {P_1V_1} {T_1} =\frac {P_2 V_2}{T_2}$

$P_2=\frac {1.1×4.5×372}{312×1.2}$

$P_2 =4.9atm$