A beaker contains 11.30 M osimium (lll) fluoride in 0.0673 liters of solution. How many grams of osimium (lll) fluoride are dissolved in this solution?
It is given that:
Molarity (M) = 11.30 M
Volume (V) = 0.0673 liters
So Moles of osimium(III) fluoride "=11.30\\times0.0673=0.76moles"
Now mass of osimium(III) fluoride "=moles\\times molar mass"