Question

1. Combining chlorine gas and oxygen gas can produce dichlorine heptoxide.  If 87.8 L of oxygen is combined with 62.5 L of chlorine, how many grams of dichlorine heptoxide will be produced?

Answer 1

2Cl₂(g)+7O₂(g)$\to$ 2Cl₂O₇(g)

Moles of Cl₂=(87.8*1)/24=3.658moles

Moles of O₂=(62.5*1)/24=2.604moles

If 7=2.604moles

$\therefore$ 2=(2*2.604)/7=0.74405moles

RMM of Cl₂O₇=182.901g/mol

Mass of Cl₂O₇=(182.901*0.74405)

=136.09g