Answer to Question #198133 in General Chemistry for universa

Question

What mass of sodium hydroxide is needed to produce 75g of sodium sulfate when reacted with excess sulphuric acid?

Answer 1

2NaOH+H2SO4=Na2SO4+2H2O

v=m/M

M(Na2SO4)=142g/mol

v(Na2SO4)=75g/142g/mol=0.53mol

v(NaOH)=2v(Na2SO4)=1.1mol

M(NaOH)=40g/mol

m(NaOH)=1.1mol*40g/mol=44g