Answer to Question #197673 in General Chemistry for isioma

Question

Calculate the solubility of kcl in g/dm³ if 5gram of the salt was dissolved in 50cm³ of water at 40 degree celius

Answer 1

Using the information provided and the conversion between cm³ and dm³ ($1\,dm^3= 1000\,cm^3$) we calculate the solubility as:

$S = \frac{m}{V} = \frac{5\,g\,KCl}{50\,\cancel{cm^3}}*\frac{1000\,\cancel{cm^3}}{1\,dm^3}$

$S = \frac{5000\,g\,KCl}{50\,dm^3}= \frac{100\,g\,KCl}{dm^3}$

At last, we find that the solubility of KCl at 40 °C is 100 g/dm³