Answer to Question #196454 in General Chemistry for Jovanni

Question

What is the theoretical yield of vanadium that can be produced by the reaction of 40g of V2O5 with 40g of calcium based on the following chemical equation? - V2O5 + 5Ca -----> 2V + 5CaO

Answer 1

Moles of $V_2O_5= \frac{40}{181.88}=0.2199$ mol

Moles of $Ca= \frac{40}{40.078}=0.9980mol$

Hence Ca is the limiting reactant

$V_2O_5 + 5Ca ---> 2V + 5CaO$

From the equation,

Mass of $V_2O_5$ produced = $\frac{1}{5} ×0.9980×181.88 g/mol =36.30 g$