I need to make 200.0 mL of 3.00M NaOH for a titration lab. How many grams of powdered lye (NaOH) should I put in a 200.00 mL volumetric flask?
As Concentration of NaOH solution = 3.0M
Volume of NaOH solution = 850 mL = 200 / 1000 L = 0.2 L
Molar Mass of NaOH = 40 g/mol
Mass of NaOH added;
= Concentration of NaOH solution × Volume of NaOH solution × Molar Mass of NaOH
= 3.0 M × 0.2L × 40 g/mol
= 24 g
How was this problem solved?