Answer to Question #195601 in General Chemistry for devin

Question

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I. A student calculated the molarity of a solution prepared by dissolving 0.730 mol of table sugar (sucrose, C₁₂H₂₂O₁₁) in 1.8x10^3 mL of water as 4.06x10^-4 M C₁₂H₂₂O₁₁. 

 

Answer 1

Solution.

$\nu=0.730mol;$

$V=1.8\sdot10^3mL=1.8L;$

$C=\dfrac{\nu}{V};$

$C=\dfrac{0.730mol}{1.8L}=0.406M;$

The student made a mistake because he did not convert a unit of volume from milliliters to liters. After all, molarity is defined as the number of moles of solute per liter of solution.

Answer: $C=0.406M.$