Answer to Question #195075 in General Chemistry for Bryttany

Question

Some oxygen is collected in a 0.250 L container at 25.0C and 720.mmHg. How many moles of oxygen is

this?

Answer 1

We know that

1atm = 760 mmHg

So 720 mmHg=0.94atm

T=25+273=298K

R= 0.082L·atm/K·mol

V=0.025L

We will use

$PV=nRT$

0.94atm×0.25L=n×0.082L·atm/K·mol×298K

n=0.0096 mole