# Answer to Question #194916 in General Chemistry for utsho

Question #194916

Acetylene gas (C2H2), used in oxy-acetylene welding, reacts with oxygen according to the following equation:

2 C2H2           +      5 O2                            ⇒      4 CO2             +    2 H2O

f.w. 26.038           f.w.  31.9988                      f.w.  44.010         f.w.  18.015

How many grams of acetylene were burned if 286.4 grams of CO2 were produced during the combustion reaction? (Please show the major steps of calculation)

1
2021-05-19T02:26:27-0400

Balanced reaction

"2C_2H_2+5O_2\\ \\ \\ \\rightarrow 4CO_2+2H_2O"

Moles of CO2 produced = "{Given \\ mass \\over molar \\ mass} ={ \\frac{286.4g}{44g}}" =6.5 moles

By Stoichiometry we say that

2mole of acetylene produces 4 mole of CO2

By Stoichiometry wr get

Moles of acetylene required = "6.5\\over 2"

= 3.25 moles

So masd of acetylene burned

= 3.25×molar mass

=3.25×26g

=84.5 g

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