Question

Use the reaction E + F <-> 2G and the equilibrium concentrations 0.60 mol/L for E, 0.80 mol/L for F, and 1.30 mol/L for G to calculate the equilibrium constant. E, F, and G are all gases.

Answer 1

$E + F\ ^\longrightarrow_\longleftarrow\ 2G$

At equilibrium;

$E =0.60\ mol/L \\ F= 0.80\ mol/L\\ G= 1.30\ mol/L$

$K_{eq} =\dfrac{1.30²}{0.80× 0.60} = 3.521$