Question #194604

What is the molarity of a solution that has 0.75L of 0.25M Na2SO4

Expert's answer

Proportion:

0.25 mol – 1.00 L

x mol – 0.75 L

"x = \\frac{0.25 \\times 0.75}{1} = 0.1875 \\;mol"

M(Na_{2}SO_{4}) = 142.04 g/mol

"m = n \\times M = 0.1875 \\times 142.04 = 26.63 \\;g"

We need 26.63 g of Na_{2}SO_{4 }to prepare 0.75 L of 0.25 M Na_{2}SO_{4}.

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