Answer to Question #194536 in General Chemistry for Valentina

Question

8.00 L of argon is allowed to expand at 21.0 ° C to a volume of 25.0 L. If the pressure remains constant, what is the final temperature (in degrees Celsius)?

Answer 1

We have two conditions:

First condition:

$V_1=8l$

$T_1=21^0 C$

Second condition:

$V_2=25l$

$letT_2=T_2$

As pressure ,moles ,R is constant then

$V\propto T$

Hence:

$\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

$\dfrac{8}{25}=\dfrac{21}{T_2}$

$T_2= \dfrac{21\times25}{8}=65.625^0 C$