Answer to Question #193978 in General Chemistry for Madelleine Flores

Question #193978

Butane gas is combusted to produce carbon dioxide and water vapour. If 5.50 mol of butane are reacted, how many moles of water vapour are produced?


1
Expert's answer
2021-05-17T04:07:31-0400

2CH10 + 13 O2 = 8 CO2 +10 H2O


Moles of CH10  = 5.50 mol


Moles of H2O "=\\frac{10}{2}\u00d75.50=27.5 mol"



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