Butane gas is combusted to produce carbon dioxide and water vapour. If 5.50 mol of butane are reacted, how many moles of water vapour are produced?
2C4 H10 + 13 O2 = 8 CO2 +10 H2O
Moles of C4 H10 = 5.50 mol
Moles of H2O =102×5.50=27.5mol=\frac{10}{2}×5.50=27.5 mol=210×5.50=27.5mol
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