Question #193781

Calculate the heat of reaction: 2 NO(g)+O2(g)-->2NO2(g)

Expert's answer

remaining information

1/2N_{2} (g) + O_{2} (g) → NO_{2} (g), ΔH°A = 33.2 kJ .....(1)

1/2N_{2} (g) + 1/2O_{2} (g) → NO (g), ΔH°B = 90.2 kJ ....(2)

multiplying equation (1) by 2 and in equation 2 , first multiply by 2 and reverse it and then add both the equations

we get required equation

2 NO(g)+O_{2}(g)-->2NO_{2}(g)

final ="(32.2\\times2-90.2\\times)kJ=114kJ"

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